Solve the system using elimination. 3x – y = 28 3x + y = 14
Answer:
The value of x=10.5 and y=3.5.
Step-by-step explanation:
Given : Equations \(3x-y=28\) and \(x+y=14\)
To find : Solve the system using elimination?
Solution :
Equitation 1 -\(3x-y=28\)
Equation 2 - \(x+y=14\)
Eliminate y from both the equation by adding them,
\(3x-y+x+y=28+14\)
\(4x=42\)
\(x=\frac{42}{4}\)
\(x=10.5\)
Eliminate x by multiplying (2) by 3 and subtract from (1),
\(3x-y-3x-3y=28-42\)
\(-4y=-14\)
\(y=\frac{14}{4}\)
\(y=3.5\)
Therefore, The value of x=10.5 and y=3.5.