Answer:
The volume of the waste collection tank is \(2.38\times 10^7 cm^3\).
Explanation:
To calculate mass of a substance, we use the equation:
\(\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}\)
We are given:
Density of methanol= \(d = 0.788 g/cm^3\)
Mass of methanol= 18,754 kg = 18,754,000 g( 1 kg = 1000 g)
Volume of the methanol = V
Putting values in above equation, we get:
\(0.788 g/cm^3=\frac{18,754,000 g}{V}\)
\(V=\frac{18,754,000 g}{0.788 g/cm^3}\)
\(V=23,799,492.38 cm^3=2.38\times 10^7 cm^3\)
V = Volume of the methanol = Volume of waste collection tank
The volume of the waste collection tank is \(2.38\times 10^7 cm^3\).
