Answer:
\(Mass_{NH_3}= 42.5775\ g\)
Explanation:
Moles of \(N_2\):-
Mass = 35.00 g
Molar mass of \(N_2\) = 28.014 g/mol
The formula for the calculation of moles is shown below:
\(moles = \frac{Mass\ taken}{Molar\ mass}\)
Thus,
\(Moles= \frac{35.00\ g}{28.014\ g/mol}\)
\(Moles_{N_2}= 1.25\ mol\)
According to the reaction:-
\(N_2_{(g)} + 3H_2_{(g)}\rightarrow 2NH_3_{(g)}\)
1 mole of \(N_2\) on reaction forms 2 moles of \(NH_3\)
1.25 mole of \(N_2\) on reaction forms 2*1.25 moles of \(NH_3\)
Moles of \(NH_3\) = 2.5 moles
Molar mass of \(NH_3\) = 17.031 g/mol
The formula for the calculation of moles is shown below:
\(moles = \frac{Mass\ taken}{Molar\ mass}\)
Thus,
\(2.5\ mol= \frac{Mass}{17.031\ g/mol}\)
\(Mass_{NH_3}= 42.5775\ g\)
