Verified Answer :

apologiabiology

disance between (x1,y1) and (x2,y2) is
\(D= \sqrt{(x2-x1)^2+(y2-y1)^2}\)
given (-2,5)  (3,-4)
\(D= \sqrt{(3-(-2))^2+(-4-5)^2}\)
\(D= \sqrt{(5)^2+(-9)^2}\)
\(D= \sqrt{25+81}\)
D=√106
the distance is √106 units or abotu 10.2

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