Answer:
Force on the car to stop the car will be 7333 N
Explanation:
We have given the mass of the car m = 1000 kg
Initial speed of the car \(u=22m/sec\)
As the car stops so its final velocity v = 0 m/sec
Time is given as t = 3 sec
From first equation of motion we know that v = u+at
So \(a=\frac{v-u}{t}=\frac{0-22}{3}=\frac{-22}{3}=-7.33m/sec^2\)
From newton's second law we know that force F = ma
So force \(F=1000\times 7.333=7333N\)
