Data:
l (lenght) = \(2 \frac{1}{4} m\) = \(\frac{9}{4}m\)
w (widht) = \(\frac{7}{8}m\)
h (height) = \(1 \frac{1}{2} m\) = \(\frac{3}{2} m\)
V (volume) = ?
Formula:
\(V = l*w*h\)
Solving:
\(V = l*w*h\)
\(V = \frac{9}{4} * \frac{7}{8} * \frac{3}{2}\)
\(V = \frac{189}{64}m^3\)
Transforming into a mixed fraction:
.....................189 |_64 → denominator
numerator←(61)....2.→Whole part
Stays like this: \(2 \frac{61}{64}\)
Therefore:
\(V = \frac{189}{64}m^3\:\longrightarrow\:\boxed{\boxed{V=2 \frac{61}{64}m^3 }}\end{array}}\qquad\quad\checkmark\)
