Suppose a normal distribution has a mean of 20 and a standard deviation of four. A value of 26 is how many standard deviation's away from the mean?
\(26=20+6=20+\dfrac64\times4=20+1.5\times4\)
which means 26 is 1.5 standard deviations away from the mean.
Knowing that:
The standard score, or z-score, represents the number of
Standard deviations that separate a random variable x from
average.
Formula:
\(z = \frac{value-average}{standard\:deviation}\)
Data:
z = ?
value = 26
average = 20
standard deviation = 4
Solving:
\(z = \frac{value-average}{standard\:deviation}\)
\(z = \frac{26-20}{4}\)
\(z = \frac{6}{4}\)
\(\boxed{\boxed{z = 1.5}} \end{array}}\qquad\quad\checkmark\)
Answer:
\(\underline{26\:is\:1.5\:standard\:deviation\:in\:relation\:to\:the\:average.}\)