A bag contains a mixture of almonds, walnuts, and cashews. There is an equal quantity of each nut. If a nut is chosen randomly out of the bag, what is the probability that the nut is either an almond, a walnut, or a cashew? Round answer to the nearest thousandth. A. 0.333 B. 0.667 C. 0.750 D. 1
The answer is D.1
If all the nuts in the bag are of equal quantity to one another then the chance of pulling a nut out of that category is the same as the other which is 1
Answer:
Option D. 1
Step-by-step explanation:
A bag contains a mixture of almonds, walnuts and cashews in an equal quantity of each nut.
If a nut is chosen randomly out of the bag,
Each have the same probability, that the nut is either an almond, a walnut or a cashew.
P (Almond) = \(\frac{1}{3}\)
P (Walnut) = \(\frac{1}{3}\)
P (Cashew) = \(\frac{1}{3}\)
P (almond or walnut or Cashew) = P(almond) + P(walnut) + P(cashew)
P = \(\frac{1}{3}+\frac{1}{3}+\frac{1}{3}\) = \(\frac{3}{3}\)
P = 1
The probability that a nut is either an almond, a walnut or a cashew is 1.