piggy4703
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I cant remember this its not a test but i have more questions can someone pleas help with a simple way of working it

I cant remember this its not a test but i have more questions can someone pleas help with a simple way of working it class=

Verified Answer :

Ozgr

Assume that your equation is such form \(y=mx+n\) Now you must find what m and n are. Just try given points that are (x,y) = (0,-2), (1,4), (2,10), (3,16), (4,22) and (5,28) Only two of them enough to find what m and n are. I picked (0,-2), (1,4) and put them in equation. Let me show you.

For (0,-2) : \(-2=m.0+n\) then I have \(n=-2\) Now I must find m=?

I used (1,4) then \(4=m.1+ (-2)\) (I know what n is) Hence I have m=6

Therefore your equation is \(y=6x-2\) so ?=6 in picture.

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