Verified Answer :

carlosego

By definition, we have that the speed is given by:


\(v = \frac{d}{t}
\)

Where,

d: distance traveled

t: time to travel said distance

Substituting values we have:

\(v = \frac{26.2}{5.5}

v = 4.763636364
\)

Then, rounding the obtained speed we have:


\(v = 4.8 mph
\)

Answer:

Kenneth's average speed is:

v = 4.8 mph

The average speed of Kenneth is 4.8 mph during the marathon. It is the average of different speeds at multiple points.

What is the average speed?

It is the average of different speeds at multiple points. It can be calculated by dividing the total distance covered by the total time elapsed.

\(\overline{v}={\dfrac{\Delta x}{\Delta t}}\)

Where,

\(\overline{v}\) = average velocity

\({\Delta x}\)   = displacement    = 26.2 miles

\({\Delta t}\) = change in time   = 5.5 hours

Put the values in the formula,

\(\overline{v}={\dfrac{26.2}{5.5}}\\\\\overline{v}= 4.8 \rm \ miles/hour\)

 

Therefore, the average speed of Kenneth is 4.8 mph during the marathon.

Learn more about the average speed:

https://brainly.com/question/973815

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