Answer: Option (b) is the correct answer.
Explanation:
The given data is as follows.
Initial velocity, \(v_{i}\) = 32 km/hr, Final velocity, \(v_{f}\) = 54 km/h
Time (t) = 8.0 seconds.
Calculate the acceleration, using the formula as follows.
\(v_{f}\) = \(v_{i}\) + a × t
54 km/hr = 32 km/hr + a × 8 sec
(54 - 32) km/hr = a × 8 sec
22 km/hr = a × 8 sec
or, a = \(\frac{22 km/hr}{8 sec}\)
= 2.75 km/hr/sec
= 2.8 km/hr/sec (approx)
Thus, we can conclude that acceleration of the car is 2.8 km/hr/sec (approx).
