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Use the concept of specific heat to analyze the following observation.



Two pieces of metal with exactly the same mass are placed on a surface in bright sunlight. The temperature of the 1st block increases by 3°C while the temperature of the 2nd increases by 8°C. If the specific heat of the 2nd block is 0.24 J/g-K, what is the specific heat of the 1st block?

A0.3 J/g-K
B0.64 J/g-K
C1.2 J/g-K
D1.56 J/g-K



I NEED THIS ASAP!!!!!

Verified Answer :

0.64 is the correct answer.


arontrevord

0.64 J/g-K

First, if we consider the formula q=mCΔT for each block, the "q" for both are equal. Therefore,

m1C1ΔT1 = m2C2ΔT2

Since the masses are the same, cancel them. Leaving

C1ΔT1 = C2ΔT2

Plug in the known values for C and &DeltaT. Solve for C1. This will result in 0.64 J/g-K.

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