Please answer all six questions! : )
\(18-(\sqrt[3]{27})^3=18-27=-9\)\(\left(\sqrt[3]{-\dfrac18}\right)^3+3\dfrac34=-\dfrac18+\dfrac{15}4=\dfrac{29}8=3\dfrac58\)\(5\sqrt[3]{729}-24=5\times9-24=21\)\(\dfrac14-2\sqrt[3]{-\dfrac1{216}}=\dfrac14-2\times\left(-\dfrac16\right)=\dfrac7{12}\)\(54+\sqrt[3]{-4096}=54-16=38\)\(4\sqrt[3]{8000}-6=4\times20-6=74\)