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Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a mass of 1.30 kg and a specific heat of 3.41 J/(gi°C). If the initial temperature of the calorimeter is 25.5°C, what is its final temperature?



A.30.9°C

B.34.5°C

C.44.0°C

D.51.5°C

Verified Answer :

Edufirst

Data:

Heat = 24 KJ = 24,000 J
mass = 1.3kg = 1300 g
Cs = 3.41 J / (g °C)
Ti = 25.5 °C
Question: Tf


Formula: Heat = mCsΔT =>

ΔT = Heat / (mCs) = 24000J/[1300g*3.41J/(g°C)] = 5.4 °C

ΔT = Tf - Ti => Tf = ΔT + Ti = 25.5°C + 5.4°C = 30.9°C

Answer: 30.9°C

Eduard22sly

The final temperature of the calorimeter is 30.9 °C (Option A)

Data obtained from the question

  • Heat (Q) = 24 KJ = 24 × 1000 = 24000 J
  • Mass (M) = 1.30 kg = 1.3 × 1000 = 1300 g
  • Specific heat capacity (C) =  3.41 J/gºC
  • Initial temperature (T₁) = 25.5 °C
  • Final temperature (T₂) =?

How to determine the final temperature

The final temperature of the calorimeter can be obtained as illustrated below:

Q = MC(T₂ – T₁)

24000 = 1300 × 3.41 (T₂ – 25.5)

24000 = 4433 (T₂ – 25.5)

Divide both side by 4433

24000 / 4433 = T₂ – 25.5

5.4 = T₂ – 25.5

Collect like terms

T₂ = 5.4 + 25.5

T₂ = 30.9 °C

Thus, the final temperature of the calorimeter is 30.9 °C

Learn more about heat transfer:

https://brainly.com/question/6363778

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