If x = 2 and y = 1, then 3(y – 1) + 2x2 =
3(1-1) +2x23-1+42+4=6
Another Question! :)
You would substitute 2 for x in the equation and I for y in the equation.
3(y - 1) + 2x 2 =
3(1 - 1) + 2(2) x 2 =
3(0) + 4 x 2 =
0 +8 =
8
Your answer would be 8.
Hope I helped! :)
