Answer:
Resultant, d = 19.9 meters
Explanation:
It is given that,
The bear heads 55 degrees north of west for 15.0 m; then it turns and heads to the west for another 7.00 m. The attached figure shows the whole scenario.
The net displacement of bear due north is given by :
\(d_n=15\ sin\theta\)
\(d_n=15\ sin(55) = 12.28\ m\)
The net displacement of bear due west is given by :
\(d_w=15\ cos\theta+7\)
\(d_w=15\ cos(55)+7=15.60\ m\)
Let d is the resultant displacement of a bear searching for berries on the mountain. It can be calculated as :
\(d=\sqrt{d_n^2+d_w^2}\)
\(d=\sqrt{12.28^2+15.60^2}\)
d = 19.85 meters
or
d = 19.9 meters
So, the resultant displacement of a bear is 19.9 meters. Hence, this is the required solution.
