Verified Answer :

Willchemistry

Moles ratio:

1 S + 1 O2 = 1 SO2

1 mole S -------------- 1 mole SO2
? moles S ------------ 0.567 moles SO2

0,567 x 1 / 1

= 0.567 moles of S

Answer:

\(0.567mol SO_{2}\)

Explanation:

We have the reaction

\(S+ O_{2}\longrightarrow So_{2}\)

we balance the equation

\(S+ O_{2}\longrightarrow So_{2}\)

In this case the equation is already balanced

We use stoichiometric relations to solve it.

we know that 1 mol of sulfur produces 1 mol of \(SO_{2}\) (we know it by the coefficients of balancing of the equation, which in this are equal to 1)

Now how many moles of sulfur are needed to produce 0.567 moles of \(SO_{2}\)

\(1mol S\longrightarrow 1 mol SO_{2}\\ x\longrightarrow 0.567mol SO_{2}\\ x=\frac{0.567 mol SO_{2}.1molS}{1molSO_2} =0.567mol SO_{2}\)

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