Answer:
\(3m^2n\)
Step-by-step explanation:
Since,
\(48m^5n=3\times 2\times 2\times 2\times 2\times m\times m\times m\times m\times m\times n\)
\(81m^2n^2=3\times 3 \times 3\times 3\times m\times m\times n\times n\)
Thus,
\(\text{GCF of }48m^5n\text{ and }81m^2n^2=3\times m\times m\times n\)
\(=3m^2n\)
