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dkornelsen10 dkornelsen10
  • 01-02-2017
  • Mathematics
Answered

Solve the equation on the interval [0, 2π).



cos x + 2 cos x sin x = 0

Api/2, 7pi/6, 3pi/2


Bpi/2, 7pi/6, 3pi/2, 11pi/6


C7pi/6, 11pi/6 2π

Verified Answer :

LammettHash
LammettHash LammettHash
  • 01-02-2017

\(\cos x+2\cos x\sin x=\cos x(1+2\sin x)=0\)

\(\cos x=0\) in the given interval when \(x=\dfrac\pi2,\dfrac{3\pi}2\).

\(1+2\sin x=0\implies \sin x=-\dfrac12\) when \(x=\dfrac{7\pi}6,\dfrac{11\pi}6\).

Answer Link
anleib1016 anleib1016
  • 13-05-2020

Answer: -(sqrt 3/2)

Step-by-step explanation:

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