A baseball team played 161 regular season games. The ratio of the number of games they won to the number of games they lost was 3/4 How many games did they win? How many games did they lose?
Answer:
The team won 69 games.
The team lost 92 games.
Step-by-step explanation:
We have been given that the ratio of the number of games a baseball team won to the number of games they lost was 3/4.
This means that out of every 7 (3+4) games they won 3 games and lost 4 games.
So the proportion for winning the game to total games will be 3/7.
\(\frac{\text{Number of games the team won}}{\text{Total number of games}}=\frac{3}{7}\)
As they played 161 games, so upon substituting 161 in our above proportion we will get,
\(\frac{\text{Number of games the team won}}{161}=\frac{3}{7}\)
\(\frac{\text{Number of games the team won}}{161}*161=\frac{3}{7}*161\)
\(\text{Number of games the team won}=3*23\)
\(\text{Number of games the team won}=69\)
Therefore, the team won 69 games.
Now let us find the number of games the team lost.
The proportion for loosing the game to total games will be 4/7.
\(\frac{\text{Number of games the team lost}}{\text{Total number of games}}=\frac{4}{7}\)
As they played 161 games, so upon substituting 161 in our above proportion we will get,
\(\frac{\text{Number of games the team lost}}{161}=\frac{4}{7}\)
\(\frac{\text{Number of games the team lost}}{161}*161=\frac{4}{7}*161\)
\(\text{Number of games the team lost}=4*23\)
\(\text{Number of games the team lost}=92\)
Therefore, the team lost 92 games out of 161 games.