Verified Answer :

z^25 needs to be z^24 to make a perfect cube

if z^24 then

125x^18y^3z^24 = 5^3 (x^6)^3 y^3 (z^8)^3

Answer:

\(z^{25}\) has to be changed.

Step-by-step explanation:

The given monomial is \(125x^{18}y^{3}z^{25}\).

If we see the separate terms of the monomial then we find that each term can be written in perfect cube form except z.

125 = 5³

\(x^{18}=(x^{6})^{3}\)

y³ is in cube form

\(z^{25}\) is the only term which can be written in the perfect cube form if it is \(z^{24}=(z^{8})^{3}\) or \(z^{27}=(z^{9})^{3}\)

So the answer is \(z^{25}\)

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