Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -36 and 2304, respectively.
\(a_5=ra_4=r^2a_3=r^3a_2\)
\(2304=-36r^3\implies r=-4\)
Since \(a_2=ra_1\implies -36=-4a_1\implies a_1=9\), the sequence takes the form
\(a_n=(-4)^{n-1}a_1=9(-4)^{n-1}\)
Answer:
\(a_n=9*4^n^-^1\)
Step-by-step explanation:
Substitute the value of n for the nth term
\(a_2=9*4^(^2^)^-^1\)
Subtract 1 from 2
\(a_2=9*4\)
Multiply 9 by 4
\(a_2=36\)
This is the only option from the choices that has a second term of 36 so it is the only option that satisfies the requirements.