Answer:
\(\frac{1}{y^{7z}}\)
Step-by-step explanation:
Given the expression:
\(-(14)^0 \cdot y^{-7z}\)
We know that:
\(a^0 =1\)
\(a^{-1} = \frac{1}{a}\)
then;
\(1 \cdot y^{-7z}\)
⇒\(y^{-7z}\)
⇒\(\frac{1}{y^{7z}}\)
Therefore, the simplified form of \(-(14)^0 \cdot y^{-7z}\) is, \(\frac{1}{y^{7z}}\).
