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Write net ionic equation for Lead 2 acetate and ammonia


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Pb(C2H3O2)2(aq) + 2NH3(aq) = Pb(NH3)2(aq) + 2C2H3O2(aq)

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Verified Answer :

MissPhiladelphia

The net ionic equation for Lead 2 acetate and ammonia would be written as follows:

(CH3COO)2Pb (aq) + (NH4)2SO4 (aq) --> 2CH3COONH4 (aq) + PbSO4 (s) 

Ionic eq: 2CH3COO^- (aq) + Pb^2+ (aq) + 2NH4^+ (aq) + SO4^2- (aq) --> 2CH3COO^- (aq) + 2NH4^+ (aq) + PbSO4 (s) 

Spectator ions: CH3COO^-, NH4^+ 

Pb^2+ + SO4^2- --> PbSO4 (s)

Hey

Pb^2+ + SO4^2- --> PbSO4 (s)

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