\(W + \frac{1}{4} = \frac{5}{6}\)
Solving:
least common multiple (4,6)
4,6| 2
2,3| 2
1,3| 3
1,1|------- 223 = 12
LCM of 4 and 6, it is 12
Now, we have:
\(W + \frac{1}{4} = \frac{5}{6}\)
\(\frac{12W}{12}+ \frac{3}{12} = \frac{10}{12}\)
cancel denominators
\(\frac{12W}{\diagup\!\!\!\!\!12}+ \frac{3}{\diagup\!\!\!\!\!12} = \frac{10}{\diagup\!\!\!\!\!12}\)
\(12W + 3 = 10\)
Keep the number with the incognito on the left and swap the number without incident to the right, changing its signal.
\(12W = 10 - 3\)
\(12W = 7\)
\(\boxed{\boxed{W = \frac{7}{12}}}\)
Answer:
\(\boxed{\boxed{W = \frac{7}{12}}}\) \(\end{array}}\qquad\quad\checkmark\)
