Verified Answer :

\(\bf g(x) = -0.5x^2+3x+4\qquad g(x)=-5\qquad thus \\ \quad \\ -5=-0.5x^2+3x+4\implies \cfrac{1}{2}x^2-3x-9=0\leftarrow \times 2\textit{ both sides} \\ \quad \\ x^2-6x-18=0\)

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