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The scatter plot below shows the number of pizzas sold during weeks when different numbers of coupons were issued. The equation represents the linear model for this data.







y = 3.4x + 43







According to the model, what is the average number of pizzas sold in one night if no coupons are issued?






A0


B21


C43


D60


E70

The scatter plot below shows the number of pizzas sold during weeks when different numbers of coupons were issued. The equation represents the linear model for class=

Verified Answer :

InesWalston

Answer:

The average number of pizzas sold in one night if no coupons are issued is 43.

Step-by-step explanation:

In the scatter plot the average number of pizzas sold is represented on x and number of coupons issued is represented on y.

The trend line of this linear model is \(y = 3.4x + 43\)

So, when no coupons are issued then the value of x becomes 0, then putting the value of x in the equation,

\(\Rightarrow y=3.4(0)+43\)

\(\Rightarrow y=0+43\)

\(\Rightarrow y=43\)

Therefore, the average number of pizzas sold in one night if no coupons are issued is 43.

Answer:

The correct answer option C.

Step-by-step explanation:

Let x be the number of coupons issued.

Let y be the number of the pizzas sold.

The given equation:

\(y=3.4x+43\)

This given equation of an straight line.

Number of pizzas when no coupons were issued.

\(y=3.4x+43=3.4\times 0+43=43\)

43 number of pizzas were sold in one night.

Hence, the correct answer option C.

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