If one root of equation 2\(x^{2}\)+8x+c=0 is r1=1+\(\sqrt{5}\) then the other root will be r2=7-\(\sqrt{5}\).
What is equation?
Equation is relationship between two or more variables expressed in equal to form , Equations of two variables look like ax+by=c. It may be linear equation, quadratic equation and cubic equation.
How to find roots of equation?
We have been given one root of equation 2\(x^{2}\)+8x+c=11 be 1+\(\sqrt{5}\) and we have to find the other root of the equation. We know that the standard equation from roots is \(x^{2}\)-sx+p=0 in which s is sum of roots and p is the product of roots.
When we compare the standard equation from the given equation we can find that sum of roots be 8.
let the other root be z such that:
z+1+\(\sqrt{5}\)=8
z=8-1+\(\sqrt{5}\)
=7+\(\sqrt{5}\)
Hence if one root of equation 2\(x^{2}\)+8x+c=0 is r1=1+\(\sqrt{5}\) then the other root will be r2=7-\(\sqrt{5}\).
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