Verified Answer :

(n^3)^3 · (n^4)^5

=n^9 · n^20

=n^29

Answer:

\((n^{29}\).

Step-by-step explanation:

Given : \((n^{3})^{3} * (n^{4})^{5}\).

To find : Find the product.

Solution : We have given that

\((n^{3})^{3} * (n^{4})^{5}\).

By the exponent rule 1 ) \((x^{a})^{b} = x^{ab}\).

           Same base rule 2) \(x^{a}* x^{b} = x^{a +b}\).

Then ,

\((n^{3})^{3} * (n^{4})^{5}\) = \((n^{9}* (n^{20}\).

Now, by rule 2.

\((n^{3})^{3} * (n^{4})^{5}\) = \((n^{29}\).

Therefore,  \((n^{29}\).

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