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Use the Integral Test to determine whether the series is convergent or divergent. (If the quantity diverges, enter DIVERGES.)

Use the Integral Test to determine whether the series is convergent or divergent. (If the quantity diverges, enter DIVERGES.) class=

Verified Answer :

\(\displaystyle\sum_{n=1}^\infty\frac2{(2n+1)^3}<\int_1^\infty\frac2{(2x-1)^3}\,\mathrm dx\)

If the integral converges, then so will the sum.

Let \(y=2x-1\), so that \(\mathrm dy=2\,\mathrm dx\). Then the integral is

\(\displaystyle\int_1^\infty\frac{\mathrm dy}{y^3}=\lim_{c\to\infty}\int_1^c\frac{\mathrm dy}{y^3}\)
\(\displaystyle=\lim_{c\to\infty}-\frac1{2y^2}\bigg|_{y=1}^{y=c}\)
\(\displaystyle=\lim_{c\to\infty}-\frac1{2c^2}+\frac1{2\times1^2}\)
\(=\dfrac12\)

so the sum converges by the integral test (to some number less than 1/2).