A solution with a ph of 5 has how many more protons in it than a solution with a ph of 7?
you're moving two steps from 7 to 5 (10 x10 = 100), so 100 times more protons would be the appropriate response.
Answer:
A solution with a pH of 5 has\(9.9\times 10^{-6} M\) more protons in it than a solution with a pH of 7.
Explanation:
The pH of the solution is negative logarithm of hydrogen ion concatenation in the aqueous solution. Mathematically written as:
\(pH=-\log [H^+]\)
1) A solution with a pH of 5 :
\(5=-\log[H^+]\)
\([H^+]=10^{-5} M\)
2) A solution with a pH of 7 :
\(7=-\log[H^+]'\)
\([H^+]'=10^{-7} M\)
\([H^+]>[H^+]'\)
Difference in concentration of hydrogen ions or protons in both solutions:
\([H^+]-[H^+]'=10^{-5}M-10^{-7} M=9.9\times 10^{-6} M\)