How do you simplify(n!)^2/(n+1)!(n-1)!
We haven n! = (n-1)! x n and (n+1)! = n! x (n + 1);Then, (n!)^2 = n! x n! = n! x (n-1)! x n;And (n+1)!(n-1)! = n! x (n + 1) x (n-1)!;Finally, [n! x (n-1)! x n] / [n! x (n + 1) x (n-1)!] = (n+1)/n;
