Verified Answer :

Answer : The mass of calcium phosphate is, 0.0713 grams

Explanation : Given,

Moles of calcium phosphate, \(Ca_3(PO_3)_2\) = \(2.3\times 10^{-4}mole\)

Molar mass of calcium phosphate, \(Ca_3(PO_3)_2\) = 310.18 g/mole

Formula used :

\(\text{Moles of }Ca_3(PO_3)_2=\frac{\text{Mass of }Ca_3(PO_3)_2}{\text{Molar mass of }Ca_3(PO_3)_2}\)

Now put all the given values in this formula, we get the mass of calcium phosphate.

\(2.3\times 10^{-4}mole=\frac{\text{Mass of }Ca_3(PO_3)_2}{310.18g/mole}\)

\(\text{Mass of }Ca_3(PO_3)_2=0.0713g\)

Therefore, the mass of calcium phosphate is, 0.0713 grams

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We have that for the Question "How many grams are in 2.3×10^-4 moles of calcium phosphate, Ca3 (PO3)2" it can be said that the grams of 2.3×10^-4 moles of calcium phosphate is

m=71310^{-4}grams


From the question we are told

How many grams are in 2.3×10^-4 moles of calcium phosphate, Ca3 (PO3)2


Generally the equation for the calcium phosphate  is mathematically given as

Ca3 (PO3)2

Therefore

Ca3 (PO3)2 has a molar mass of

310 g/mol.

Hence

2.3×10^-4 moles of calcium phosphate will have

m=2.310^{-4} 310

m=71310^{-4}grams

Therefore

The grams of 2.3×10^-4 moles of calcium phosphate is

m=713*10^{-4}grams


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