Solve by factoring 4x squared -12x-16=0
\(4x^2-12x-16=0\ \ \ | put\ 4\ in\ front\ of\ the\ bracket\\\\ 4(x^2-3x-4)=0\ \ \ | write\ -3x\ as\ x-4x\\\\ 4(x^2+x-4x-4)=0\\\\4(x-4)(x+1)=0\\\\ x=4\ or\ x=-1\)
Find the factors of -16 (2x-8)(2x+2)=0So the factors were -8 and 2 2x(-8)= -16x | 2x(2)= 4 -16x+4=-12xAnd now find the x2x-8=0 2x+2=02x=8 2x=-2X=4 X=-1so x is equal to 4 & -1
