How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal? Show all of the work used to solve this problem.

2 K + F2 ---> 2 KF

Question

30-01-2017
Chemistry

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How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal? Show all of the work used to solve this problem.

2 K + F2 ---> 2 KF

Verified Answer :

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Willchemistry Willchemistry · Answer 1 · 2017-01-30T17:08:47-05:00

1) Molar mass:

K =  39.0983 g/mol
F₂ =  37.99 g/mol

moles ratio:

2 K + F₂   = 2 KF

2 x 39.0983 g K ----------------- 37.99 g F₂
23.5 g K -------------------------- ( mass of F₂)

mass of F₂ = 23.5 x 37.99 / 2 x 39.0983

mass of F₂ = 892.765 / 78.1966

mass of F₂ = 11.4169 g

Therefore:

37.99 g F₂------------------ 22.4 L ( at STP)
11.4169 g F₂ --------------- ( volume F₂ )

Volume F₂ = 11.4169 x 22.4 / 37.99

Volume F₂ = 255.73856 / 37.99

Volume F₂ = 6.731 L

How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal? Show all of the work used to solve this problem. 2 K + F2 ---> 2 KF

Verified Answer :

Related Questions

How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal? Show all of the work used to solve this problem.

2 K + F2 ---> 2 KF