how to divide 4y^3-14y^2/2y^2
[ 4y^3 - 14y^2 ] / [ 2y^2 ]= [ 4y^(2+1) - 14y^2 ] / [ 2y^2 ]= [ 4y^2 y - 14y^2 ] / [ 2y^2 ]= [ 2y^2 2y - 2y^2 7 ] / [ 2y^2 ]= [ 2y^2 (2y - 7) ] / [ 2y^2 ]= 2y - 7 <----- this is the answerI hope this helps. =)
