Data:
m (Sample Mass) = ?
n (Number of moles) = 0.714 mol
MM (Molar Mass) of Mercury (I) Chloride (\(Hg_{2} Cl_{2}\))
Hg = 2200.59 = 401.18 amu
Cl = 235.453 = 70.906 amu
----------------------------------------
Molar Mass \(Hg_{2} Cl_{2}\) = 401.18 + 70.906 = 472.086 ≈ 472.09 amu or 472.09 g/mol
Formula:
\(n = \frac{m}{MM}\)
Solving:
\(n = \frac{m}{MM}\)
\(0.714 = \frac{m}{472.09}\)
\(m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark\)
Answer:
By approximation would be letter D) 337.2 g
