Answer:Pressure of the air inside the sealed container will get change 2 atm when absolute temperature is doubled.
Explanation:
According to question , Volume is constant
According to Gay Lussac's Law:
\(Pressure\propto Temperature\) (at constant temperature)
\(\frac{P_1}{T_1}=\frac{P_2}{T_2}\)
At STP, the temperature ,\(T_1=273 K\)
At STP, the pressure =\(P_1=1 atm\)
On doubling the absolute temperature the pressure changes \(P_2\):
On doubling the temperature= \(T_2=2\times T_1\)
\(P_2=\frac{1 atm\times 2\times 273 K}{273 K}=2 atm\)
Pressure of the air inside the sealed container will get change 2 atm when absolute temperature is doubled.
