Dawson14
Answered

Harper's house is 30 feet wide and 45 feet long. On a scale drawing, the house is 4 inches wide and 6 inches long, and Harper's bedroom is 1.2 inches wide and 1.6 inches long.


What are the actual measurements of Harper's bedroom?



Harper's bedroom is ____ feet wide and ____ feet long

Verified Answer :

yashddsy26

so 30 ft is equal to 4 Inc on scale !
therefore 1.2 on scale will be (30/4)×1.2= 9 ft wide !!

6 Inc on scale is equal to 45 feet on actual
so 1.6 will be (45/6)×1.6= 12 ft long


so answer is 9 ft wide and 12 ft long !!

calculista

Answer:

Harper's bedroom is \(9\) feet wide and \(12\) feet long

Step-by-step explanation:

step 1

Find the scale of the drawing

we know that

Harper's house is \(30\) feet wide and \(45\) feet long. On a scale drawing, the house is \(4\) inches wide and \(6\) inches long

The scale is equal to

\(\frac{4}{30}\frac{inches}{feet} =\frac{6}{45}\frac{inches}{feet}=\frac{1}{7.5}\frac{inches}{feet}\)

step 2

Find the the actual measurements of Harper's bedroom

we know that

Harper's bedroom on a scale drawing is \(1.2\) inches wide and \(1.6\) inches long

The scale drawing is \(\frac{1}{7.5}\frac{inch}{feet}\)

therefore

To obtain the actual measurements multiply the measurements on a scale drawing by \(7.5\)

so

\(wide=1.2*7.5=9\ ft\)

\(long=1.6*7.5=12\ ft\)

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