A 10.0 Molar solution is used to make 100. mL a 5.00 Molar solution. How much of the original solution is used?

A10.0 mL
B50.0 mL
C500. mL
D100.0 mL

Verified Answer :

Data: 
\(M_{concentrated} = 10\:mol\)
\(V_{concentrated} = ?\)
\(M_{dilute} = 5\:mol\)
\(V_{dilute} = 100\:mL\)

Formula: Dilution Calculations

\(M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}\)

Solving:


\(M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}\)
\(10 * V_{concentrated} = 5 * 100\)
\(10V_{concentrated} = 500\)
\(V_{concentrated} = \frac{500}{10}\)
\(\boxed{\boxed{V_{concentrated} = 50\:mL}} \end{array}}\qquad\quad\checkmark\)

Answer:
B. 50.0 mL