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How does the electric force between two charged particles change if one particle's charge is increased by a factor of 2?

AIt is increased by a factor of 2.
BIt is decreased by a factor of 2.
CIt is decreased by a factor of 4.
DIt is increased by a factor of 4.

Verified Answer :

226535

if one of the charge is doubled, the electric potential energy would be doubled too

Coulomb's Law :

Force = K(q1q2/r^2)  

K = constant

q1 = charge 1

q2 = charge 2

r = radius

If the charge of the particles are same then,

q1= 1

q2=1

r=2 (consider /by default)

F = (1)(1)/(2)^2 = 0.25

If charge is the only variable, then the force will be ½ the original force. If the charge on one particle (q) is increased by a factor of 2.  For example...

q1 = 2

q2 = 1

r = 2(by default)

F = (2)(1)/(2)^2 = 0.5

0.25 < 0.5 , the electric force get increased by the factor of 2.

What is electric force ?

“The attractive or repulsive interaction between any two charged objects is an electric force.”

What is Coulombs law ?

“Coulombs law states that like charges repel and opposite charges attract, with a force proportional to the product of the charges and inversely proportional to the square of the distance between them”.

Know more about electric force here

https://brainly.com/question/2526815

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