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munnylala
munnylala munnylala
  • 30-01-2017
  • Mathematics
Answered

Calculate the gradients of the curve at the points where y is given.
y=2x²+3x , y=2
help me pls

Verified Answer :

LammettHash
LammettHash LammettHash
  • 30-01-2017

\(y=2x^2+3x\implies y'=4x+3\)

When \(y=2\), you have

\(2=2x^2+3x\iff 2x^2+3x-2=(2x-1)(x+2)=0\implies x=\dfrac12,-2\)

When \(x=\dfrac12\), the gradient is \(4\times\dfrac12+3=5\).

When \(x=-2\), the gradient is \(4\times(-2)+3=-5\).

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