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Martin has a combination of 33 quarters and dimes worth a total of $6. Which system of linear equations can be used to find the number of quarters, q, and the number of dimes, d, Martin has?


Aq + d = 6

25q + 10d = 33


Bq + d = 6

0.25q + 0.1d = 33


Cq + d = 33

25q + 10d = 6


Dq + d = 33

0.25q + 0.1d = 6

Verified Answer :

Answer:

q + d = 33  0.25q + 0.1d = 6

Step-by-step explanation:

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JeanaShupp

Answer: D) . \(q+d=33\)

\(0.25q+0.1d=6\)

Step-by-step explanation:

We know that $1 = 4 quarters

⇒ 1 quarter = @@MATH_TOKEN_2@@

$1 = 10 dimes

1 dime =\(\frac{1}{10}=\$0.1\)

Let 'q' be the number of quarters and 'd' be the number of dimes.

Since, Martin has a combination of 33 quarters and dimes worth a total of $6.

\(q+d=33\)

\(0.25q+0.1d=6\)

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