Answer:
The second number in the sequence is 81.
Step-by-step explanation:
The sum of 4 consecutive integers is 326.
Let us assume that the first number is x. So the next numbers would be,
\(=x+1,x+2,x+3\)
Sum of these number would be,
\(=x+(x+1)+(x+2)+(x+3)\)
As it is given as 326, so
\(\Rightarrow x+(x+1)+(x+2)+(x+3)=326\)
\(\Rightarrow x+x+1+x+2+x+3=326\)
\(\Rightarrow 4x+6=326\)
\(\Rightarrow 4x=326-6\)
\(\Rightarrow 4x=320\)
\(\Rightarrow x=80\)
Hence, the second number (x+1) will be 81.
