What are the coefficients for the binomial expansion of (a + b)^3?
The coefficients are given by \(\dbinom 3k=\dfrac{3!}{k!(3-k)!}\) where \(k\in\{0,1,2,3\}\). These are, in order, \(\{1,3,3,1\}\).
So the expansion is
\((a+b)^3=1a^3+3a^2b+3ab^2+1b^3\)
Answer:
Required coefficient :coefficient of 1st, 2nd, 3rd and 4th term are 1, 3,3,1 respectively.
Explanation:
Formula for binomial expansion is \((a+b)^n=^nC_0\cdot a^n\cdot b^0+^nC_1\cdota^(n-1)\cdot b^1+------b^n\)
We will substitute the values a=a, b=b and n=3 in the formula for binomial expansion we will get
\(^3C_0\cdot a^3\cdot b^0+^3C_1\cdot a^2\cdot b^1+^3C_2\cdot a^1\cdot b^2+^3C_3\cdot a^0\cdot b^3\)
After simplification of the terms we will get
\(a^3+3\cdot a^2\cdot b+3\cdot a\cdot b^2+b^3\)
Since, \(^nC_r=\frac{n!}{(r!)(n-r)!}\)
Therefore the required coefficient : coefficients of 1st, 2nd, 3rd and 4th term are 1, 3,3,1 respectively.