Answer: 493 grams
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number \(6.023\times 10^{23}\) of particles.
To calculate the number of moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadro's number}}=\frac{9.27\times 10^{24}}{6.023\times 10^{23}}=15.4moles\)
1 mole of \(CH_3OH\) weighs = 32 g
15.4 moles of \(CH_3OH\) weigh = \(\frac{32}{1}\times 15.4=493g\)
Thus mass of \(9.27\times 10^{24}\) molecules of methanol weigh 493 grams.
