Solve the following equation for g: 2(g-h)=b+4
b=2g-2h-4 this is correct
\(2(g-h)=b+4\\ 2g-2h=b+4\\ 2g=2h+b+4\\ g=\frac{2h+b+4}{2}=h+\frac{b}{2}+2\\\\ g=h+\frac{b}{2}+2\)
