Answer:
Electric potential, V = 19.2 volts
Explanation:
In this case we need to find the electric potential due to the nucleus of hydrogen at a distance of \(7.5\times 10^{-11}\ m\). For this we must know the concept of electric potential. It is the work done in moving a charged particle in electric field from zero to a particular point. Its formula is given by :
\(V=\dfrac{kq}{r}\)
q is the charge of nucleus of hydrogen i.e. proton
\(V=\dfrac{9\times 10^9\times 1.6\times 10^{-19}}{7.5\times 10^{-11}}\)
\(V=19.2\ \text{volt}\)
So, the electric potential due to the nucleus of hydrogen at a given distance is 19.2 volts. Hence, this is the required solution.