Let AB be the directed line segment beginning at point A(0,4) and ending at point B(9,8). Find the point P on the line segment that partitions the line segment into the segments AP and PB at a ratio of 1:2.
Answer:
\((3,\frac{16}{3})\)
Step-by-step explanation:
When a line segment with the end points \((x_1,y_1)\) and \((x_2,y_2)\) is divided by a point in the line segment in the ratio m : n,
Then the coordinates of this point are,
\((\frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n})\)
Thus, the coordinates of point P that divides a line segment having end points \(A(0,4)\) and \(B(9,8)\) in the ratio of 1 : 2,
\((\frac{1\times 9+2\times 0}{1+2},\frac{1\times 8+2\times 4}{1+2})\)
\((\frac{9}{3},\frac{16}{3})\)
\((3,\frac{16}{3})\)