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a pure silver ring contains 2.60 *10^22 silver atoms. How many moles of silver atoms does it contain?

Verified Answer :

Answer: The given number of atoms is contained in 0.0432 moles.

Explanation:

We are given:

Number of silver atoms = \(2.60\times 10^{22}\)

According to mole concept:

\(6.022\times 10^{23}\) number of atoms are contained by 1 mole of element

So, \(2.60\times 10^{22}\) number of atoms will be contained in = \(\frac{1}{6.022\times 10^{23}}\times 2.60\times 10^{22}=0.0432mol\) of silver.

Hence, the given number of atoms is contained in 0.0432 moles.

Eduard22sly

The silver ring contains 0.043 mole of silver.

From Avogadro's hypothesis, we understood that:

6.02×10²³ atoms = 1 mole of Silver

With the above information in mind, we can calculate the number of mole of 2.60×10²² atoms of silver. This can be obtained as follow:

6.02×10²³ atoms = 1 mole of Silver

Therefore,

2.60×10²² atoms = 2.60×10²² / 6.02×10²³

2.60×10²² atoms = 0.043 mole of Silver.

Therefore, the silver ring contains 0.043 mole of silver.

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